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Let's learn how Hill Cipher works and everything you need to know about Hill Cipher with its implementation.
Enter plain-text: meet Enter block size of matrix: 2 Enter key Matrix 3 1 5 2 Encrypted Text is: OQ FG Enter key Inverse Matrix: 2 -1 -5 3 Decrypted Text is: ME ET. Encryption and Description Text Using Hill Cipher Algorithm with Java Programming. This program using Netbean IDE. Plaintext only uses alphabetic, without nu.
When you are sending a text message to a friend, you don't want your message to be manipulated or misused by an intruder. In order to avoid this, we need to convert the plain text data to a ciphertext. Before getting into this conversion let us first know what a ciphertext is.
Ciphertext
A ciphertext is a formatted text which is not understood by anyone. Ntfs for mac remove. Hill cipher is one of the techniques to convert a plain text into ciphertext and vice versa. There are two parts in the Hill cipher – Encryption and Decryption.
Encryption – Plain text to Cipher text
Encryption is converting plain text into ciphertext. The working is shown below:
Input :
1.Plain text that has to be converted into ciphertext.
2.A KEY to encrypt the plain text
Output: Ciphertext
We have a simple formula for encryption
C = KPmod26
C is ciphertext, K is the key, P is the plain text vector.
The KEY is generally given in the problem statement. Here we are considering a 2×2 matrix. The plain text vector is represented as a column matrices that are considered one at a time. Since the key matrix is 2×2, we take each column matrix as 2×1. If the key matrix was 3×3, then each column matrix would be 3×1.
let us take an example where plain text is ‘exam‘ which has to be converted to ciphertext with key-value as now, form the column matrices into 2×1 configurations and covert the text into numeric data assigning values to each alphabet from 0 to 25.
a=0,b=1,c=2,d=3,………….,y=24,z=25
Consider the first column matrix and substitute in the above formula:
repeat this for second column matrix
Hence the final ciphertext is ‘elsc'
Decryption – Cipher text to plain text
Decryption is the conversion of ciphertext into plain text. It can be done by a simple formula
P=(K')(C) mod26
where P is the plain text, K' is the inverse key matrix, C is the ciphertext vector or the column matrices.
Input: ciphertext and key
Output: plain text.
Here the C='elsc', which are further divided into column matrices: and K=
Now let us see the working:
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1. First, find the adjacent matrix of the given key matrix
K_adj=
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2. Find the determinant of the key matrix
77-88=-11
3. Find the modulo of the determinant with 26
-11 mod26 =15=d
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4. Find the inverse number of the above result
d x d'=1 mod26
15 x d'=1 mod26
d'=7
5. Any negative numbers in K_adj should be added by 26 and then the whole matrix is multiplied by d'.
K' =
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Now, this is our new key matrix. Substituting all the values in the decryption formula, we get the required plain text.
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Sketchup crack for mac. Repeat the above step using the other column matrix
Hence the final plain text is ‘exam'.
Hill Cipher in Java
Hill Cipher in Python
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